G.MATH
VECTOR INTEGRAL CALCULUS
Directional Derivative and the Del Operator

We’ll follow up the previous lesson by deriving an equation which connects the directional derivative and the del operator.

While the definition of the directional derivative may suggest that it is hard to calculuate, it turns out that it can be expressed quite elegantly.
VIDEO LECTURE


MAIN CONCEPTS
The directional derivative and the del operator is related by the equation
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COMMENTS
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CONCEPT
Previously, we concluded with an expression of  as

The graphical illustration of  can be seen from the previous diagram or replicated below.


 

We are concern with the rate of change of  as we travel along unit vector . So, using process of differentiation, we find the derivative of  with respect to , evaluated at . Thus

Now, using the partial differentiation version of chain rule, we have

For the rate of change of  at point , we are left to evaluate these partial derivatives at  or  then

Can you spot the grad  hidden somewhere there. First recall that

,

a vector and that

also a vector. The dot product of these two vectors gives us the above expression, namely

And that my friends, is how the directional derivative is related to the gradient of  through the del operator. Lovely expression isn’t it?

Remember that the vector  needs to be a unit vector. This can be easily solved by letting  if traveling to  with a vector  whose magnitude is not unit.

All information presentated, less questions and exercises, is original content of Donny, with slight references to various books.
Video courtesy of YouTube.com service.
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