G.MATH
VECTOR INTEGRAL CALCULUS
Finding Lines of Force

Moving swiftly along from our discussion of vector fields, we shall go straight into the method of finding the lines of force for a given vector field.

In a physics perspective, suppose we know the strength of a point in a magnetic field. We then want to deduce from this information the lines of force which are generated by the magnetic field.
VIDEO LECTURE part 1


MAIN CONCEPTS
To find the lines of force of a given vector field, we use the equation
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CONCEPT
The idea behind this method is that in a given vector field  in three-space, we construct a curve by the knowledge we have of its tangents at each point.

We start by defining the curve C with the parametric equations

parametrized in terms of arc length along the curve. Do not confuse this with the vector field. This parametric equations define the curve C we are to find. We can then define the position vector to be

We do this so we can proceed with our analysis of vector differentiation.

We know from differential calculus that  is a unit vector to the curve. But our vector field  or by our parametric equations,  is a tangent to the curve at  and thus parallel to . So, for any given s, there is a scalar  such that

and by definition

We let  and by equating the i, j, and k, componenets, we have

These equations, while may be useful, is a little messy. We can put them in a more simple form by rearranging the  on one side to give

assuming  are non-zero. This is our final form of the differential equation we will use to find the lines of force.

A point to note,  need NOT be only in terms of  respectively. For example, although the i componenet of the vector field is labelled as , it can be a function of .

All information presentated, less questions and exercises, is original content of Donny, with slight references to various books.
Video courtesy of YouTube.com service.
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